# How to determine the position and size of an image?

### How to determine the position and size of an image?

Calculate the cut of the’image of an objectMethod The image size (\overline{A’B’}) can be calculated from that of the object (\overline{AB}) and the \gamma magnification. A converging lens forms theimage of an object of cut 4.0mm. Under the conditions of the experiment, the magnification is -0.5.

### What is the expression of the magnification of an optical instrument?

The object is seen with the naked eye with an angular dimension α. With a instrument magnifying, it appears with the angular dimension β. magnification G = β/α. The value of magnification can be changed by changing the eyepiece of theinstrument.

### How to calculate the magnification of an image?

Magnification and magnification. I. Conjugation formula and magnification: 1. We have created the image A’\u0011′ of AB through the lens of focal length f’=0.20m by drawing the step of 3 rays. 2. Using Thales’ theorem, find the conjugation formula: \u0010. ‘ 1 1 1 OA f.

### How to calculate the minimum viewing distance of the eye?

Simple magnification d is the minimum viewing distance of the eye. This distance depends on the user’s eye, so α also. Commercial magnification We choose the standard distance d = 25 cm (which corresponds to the eye

### What is Magnifying Magnifier?

Optical instrument: the magnifying glass A magnifying glass is a converging lens of focal length f’. When using a magnifying glass, where is the image you are looking at in relation to the lens? Is the image real or virtual?